7b^2-b-5=0

Solution for 7b^2-b-5=0 equation:

7b^2-b-5=0

We add all the numbers together, and all the variables

7b^2-1b-5=0

a = 7; b = -1; c = -5;
Δ = b2-4ac
Δ = -12-4·7·(-5)
Δ = 141
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{141}}{2*7}=\frac{1-\sqrt{141}}{14}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{141}}{2*7}=\frac{1+\sqrt{141}}{14}
$